已知\(x\),\(y\)满足\(\begin{cases}x+y-1\geqslant 0\\ x-2y-4\leqslant 0\\ 2x-y-2\geqslant 0\end{cases}\),如果目标函数\(z=\dfrac{y+1}{x-m}\)的取值范围为\([0,2),\)则实数\(m\)的取值范围为\((\quad)\)
A.\([0,\dfrac{1}{2}]\)
B.\((-∞,\dfrac{1}{2}]\) C.\((-∞,\dfrac{1}{2})\) D.\((-∞,0]\)